# -*- coding: utf-8 -*-

# Problem 6
#http://projecteuler.net/index.php?section=problems&id=6
#The sum of the squares of the first ten natural numbers is,
#1^(2) + 2^(2) + ... + 10^(2) = 385

#The square of the sum of the first ten natural numbers is,
#(1 + 2 + ... + 10)^(2) = 55^(2) = 3025

#Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

#Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.


#---------------------------
#
def diff(n):
  return square_of_sum(n) - sum_of_square(n)


#---------------------------
#
def sum_of_square(n):
  sum_of = 0
  for i in range(1, n + 1):
    sum_of = sum_of + i * i
  return sum_of

#---------------------------
#
def square_of_sum(n):
  sum_of = sum(range(1, n + 1))
  return sum_of * sum_of


print  diff(100)
